Problem: Air flows through the tube shown in the figure. Assume that air is an ideal fluid. What is the air speed v1 at point 1?

FREE Expert Solution

Bernoulli's equation:

P1+12ρv12+h1ρg=P2+12ρv22+h2ρg where ρ is the density of the moving fluid, h is the difference in height between the two points.

Continuity equation:

Q=A1v1=A2v2=Anvn

Pressure in liquids:

P=ρgh

We'll use Bernoulli's equation to solve for the velocity.

The pressure is greater in the wider cross section. P2 is greater than P1.

The elevation at points 1 and 2 is equal, h1 = h2. Thus, we can drop the terms h1ρairg and h2ρairg.

Using Bernoulli's equation:

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Problem Details

Air flows through the tube shown in the figure. Assume that air is an ideal fluid. 

What is the air speed v1 at point 1?

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