The standards equation for a wave, which propagates along the z-direction is given by:
A(ωt - kz)
v = ω/k
Comparing with the given equation:
vz = ω/-k = (-ω/k)[E0cos(ωt - (-kz)]
The electric field of a plane EM wave is given by Ex = E0cos(kz+ωt), Ey = Ez =0.
A. Determine the direction of propagation. (The answer is -z-direction but I wonder why)
B. Determine the peak value of B in terms of E0 and constants
C. Determine the direction of B at location z = 0 and t = 0 (the answer is -y-direction but I wonder why)
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