The standards equation for a wave, which propagates along the z-direction is given by:

A(ωt - kz)

v = ω/k

Comparing with the given equation:

v_{z} = ω/-k = (-ω/k)[E_{0}cos(ωt - (-kz)]

The electric field of a plane EM wave is given by E_{x} = E_{0}cos(kz+ωt), E_{y} = E_{z} =0.

A. Determine the direction of propagation. (The answer is -z-direction but I wonder why)

B. Determine the peak value of B in terms of E_{0} and constants

C. Determine the direction of B at location z = 0 and t = 0 (the answer is -y-direction but I wonder why)

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