# Problem: A particle with a charge of q = -5.30 nC is moving in a uniform magnetic field B = (-1.25 T)k. The magnetic force on the particle is measured to be F = (-7.60x10-7 N)j.Calculate the vx, the x component of the velocity of the particle. Express your answer in meters per second.

###### FREE Expert Solution

Magnetic force on moving charge:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{q}}{\mathbf{v}}{\mathbf{B}}{\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{\mathbf{\theta }}}$

The magnetic field is in the z-direction, while vx is in the x-direction.

###### Problem Details

A particle with a charge of q = -5.30 nC is moving in a uniform magnetic field B = (-1.25 T)k. The magnetic force on the particle is measured to be F = (-7.60x10-7 N)j.

Calculate the vx, the x component of the velocity of the particle. Express your answer in meters per second.