Problem: A particle with a charge of q = -5.30 nC is moving in a uniform magnetic field B = (-1.25 T)k. The magnetic force on the particle is measured to be F = (-7.60x10-7 N)j.Calculate the vx, the x component of the velocity of the particle. Express your answer in meters per second.

FREE Expert Solution

Magnetic force on moving charge:

F=qvBsinθ

The magnetic field is in the z-direction, while vx is in the x-direction. 

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Problem Details

A particle with a charge of q = -5.30 nC is moving in a uniform magnetic field B = (-1.25 T)k. The magnetic force on the particle is measured to be F = (-7.60x10-7 N)j.

Calculate the vx, the x component of the velocity of the particle. Express your answer in meters per second.

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