Relationships Between Force, Field, Energy, Potential Video Lessons

Concept

# Problem: The electric field strength is 5.00×104N/C inside a parallel-plate capacitor with a 1.90mm spacing. A proton is released from rest at the positive plate. What is the proton's speed when it reaches the negative plate?

###### FREE Expert Solution

Electric force:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{q}}{\mathbf{E}}}$

Newton's second law:

$\overline{){\mathbf{\Sigma }}{\mathbf{F}}{\mathbf{=}}{\mathbf{m}}{\mathbf{a}}}$

Uniform accelerated motion (UAM) equations:

Charge of a proton = +e = +1.6 × 10-19 C

ΣF = eE = ma

83% (468 ratings)
###### Problem Details

The electric field strength is 5.00×104N/C inside a parallel-plate capacitor with a 1.90mm spacing. A proton is released from rest at the positive plate. What is the proton's speed when it reaches the negative plate?