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Problem: A 200g oscillator in a vacuum chamber has a frequency of 2hz. When air is admitted, the oscillation decreases to 60% of its initial amplitude in 50s. How many oscillations will have been completed when the amplitude is 30% of its initial value?

FREE Expert Solution

Amplitude in damped SHM:

A(t)=A0e-bt2m

Periodic time:

T=1f

We'll determine the value of damping constant b using the conditions:

m = 0.2 kg

t = 50s

A(50s) = (60/100)A0 = 0.6A0 

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Problem Details

A 200g oscillator in a vacuum chamber has a frequency of 2hz. When air is admitted, the oscillation decreases to 60% of its initial amplitude in 50s. How many oscillations will have been completed when the amplitude is 30% of its initial value?

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