Problem: In parts A and B consider the decay of radon by alpha particle emission:222 86Rn→X+42He.Part AWhat is the nucleon number of the element X?Part BWhat is the atomic number (nuclear charge) of the element X?Part CWhat is the emitted particle X?

FREE Expert Solution

The given reaction is:

22286Rn → AZX + 42He

Part A

From the given reaction, A + 4 = 222

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Problem Details

In parts A and B consider the decay of radon by alpha particle emission:

222 86Rn→X+42He.

Part A

What is the nucleon number of the element X?

Part B

What is the atomic number (nuclear charge) of the element X?

Part C

What is the emitted particle X?

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