The angular velocity of the moon:

$\overline{){\mathbf{\omega}}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi}}{\mathbf{T}}}$

Angular momentum:

$\overline{){\mathbf{L}}{\mathbf{=}}{\mathbf{I}}{\mathbf{\omega}}}$

The moon orbits around the earth in 27.3 days.

This means that, T = 27.3 days = (27.3)(24)(3600) = 2358720 s

The angular velocity of the moon:

ω = 2π/2358720 = 2.664 × 10^{-6} rad/s

The Moon orbits around the Earth and also spin on its axis.

A. What is the angular momentum of the Moon in its orbit around Earth?

B. What is the angular momentum of the Moon in its rotation around its axis?

C. How many times larger is the orbital angular momentum than the rotational angular momentum for the Moon?

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