Combining Resistors in Series & Parallel Video Lessons

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Problem: For the circuit shown in the figure, find the current through resistor R3 =6.0 Ω (the top one) and the potential difference across resistor R3=6.0 Ω

FREE Expert Solution

Equivalent resistance for resistors in parallel:

1Req=1R1+1R2+...+1Rn

or for 2 resistors:

Req=R1R2R1+R2

Equivalent resistance for resistors in series:

Req=R1+R2+...+Rn

Ohm's law:

i=VR

R3 and R4 are in series:

R34 = R3 + R4 = 6.0 + 4.0 = 10.0 Ω

R2 and R34 are in parallel:

R234 = (1/R2 + 1/R34)-1 = (1/15 + 1/10)-1 = 6.0 Ω

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Problem Details


For the circuit shown in the figure, find the current through resistor R3 =6.0 Ω (the top one) and the potential difference across resistor R3=6.0 Ω

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