Electrostatic potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}\frac{\mathbf{k}{\mathbf{q}}_{\mathbf{1}}{\mathbf{q}}_{\mathbf{2}}}{\mathbf{r}}}$

Law of conservation of energy:

$\overline{){{\mathbf{K}}}_{{\mathbf{i}}}{\mathbf{+}}{{\mathbf{U}}}_{{\mathbf{i}}}{\mathbf{+}}{{\mathbf{W}}}_{{\mathbf{nc}}}{\mathbf{=}}{{\mathbf{K}}}_{{\mathbf{f}}}{\mathbf{+}}{{\mathbf{U}}}_{{\mathbf{f}}}}$ W_{nc} is the work done by non-conservative forces like friction.

K_{i} + U_{i} + W_{nc} = K_{f} + U_{f}

(1/2)mv_{0}^{2} + kq_{1}q_{2}/r_{i} + 0 = (1/2)mv_{f}^{2} + kq_{1}q_{2}/r_{f}

A proton follows the path shown in (Figure 1) . Its initial speed is v_{0} = 2.9×10^{6} m/s. What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units.

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