Uniform accelerated motion (UAM) equations, a.k.a. "kinematics equations":
From the third kinematic equation, a = 0 m/s2 since the velocity is constant for the motion in the first 2s.
Δx = v0t = (7.00)(2.00) = 14.0 m
The total distance traveled by the ball is given by:
d = L + Δx = 18 + 14 = 32.0 m
This distance is covered in 2.00s
Using the third kinematic equation still and knowing that a = 0 m/s2,
v0x = Δx/t = 32.0/2 = 16.0 m/s
A softball is hit over a third baseman's head with some speed v0 at an angle θ above the horizontal. Immediately after the ball is hit, the third baseman turns around and begins to run at a constant velocity V = 7.00m/s. He catches the ball t = 2.00s later at the same height at which it left the bat. The third baseman was originally standing L = 18.0m from the location at which the ball was hit.
Part A. Find v0. Use g = 9.81 m/s2 for the magnitude of the acceleration due to gravity. Express the initial speed numerically in units of meters per second to three significant figures.
Part B. Find the angle θ in degrees. Express your answer numerically in degrees to three significant figures.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Symmetrical Launch concept. You can view video lessons to learn Symmetrical Launch. Or if you need more Symmetrical Launch practice, you can also practice Symmetrical Launch practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Granucci's class at Quinnipiac University.