Magnification in a two-lens microscope:

$\overline{){\mathbf{M}}{\mathbf{=}}{{\mathbf{m}}}_{\mathbf{o}\mathbf{b}\mathbf{j}}{{\mathbf{M}}}_{\mathbf{e}\mathbf{y}\mathbf{e}}{\mathbf{=}}{\mathbf{-}}{\mathbf{\left(}}\frac{\mathbf{L}}{{\mathbf{f}}_{\mathbf{o}\mathbf{b}\mathbf{j}}}{\mathbf{\right)}}{\mathbf{\left(}}\frac{\mathbf{25}\mathbf{c}\mathbf{m}}{{\mathbf{f}}_{\mathbf{e}\mathbf{y}\mathbf{e}}}{\mathbf{\right)}}}$

The length L of the microscope is equal to the distance from the objective lens to the eyepiece.

A student makes a microscope using an objective lens and an eyepiece.

If she moves the lenses closer together, does the microscope's magnification increase or decrease?

a) The magnification of a microscope is *M *= - (*L × *25cm)/(*f*_{o}*f*_{e}) so decreasing the tube length *L* (while leaving *f*e the same) would increase the magnification

b) The magnification of a microscope is *M *= - (*L × *25cm)/(*f*_{o}*f*_{e}) so decreasing the tube length *L* (while leaving *f*e the same) would decrease the magnification

c) The magnification of a microscope is *M = -*(*f*_{o}*f*_{e})/(*L × *25cm) so decreasing the tube length *L* (while leaving *f*e the same) would decrease the magnification.

d) The magnification of a microscope is *M = -*(*f*_{o}*f*_{e})/(*L × *25cm) so decreasing the tube length *L* (while leaving *f*e the same) would increase the magnification.

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