Magnetic Force Between Parallel Currents Video Lessons

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Problem: Two long, parallel wires are separated by a distance of 0.400 m (fig. E28.29). The currents I1 and I2 have the directions shown.(a) Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other. I s the for attractive or repulsive?(b) Each current is doubled, so that I1 becomes 10.0 A and I2 becomes 4.00 A. Now what is the magnitude of the force that each wire exerts on a 1.20-m length of the other? 

FREE Expert Solution

The magnitude of the force per unit length between two-parallel current-carrying conductors is:

Fl=μ02πI1I2d

Force, F:

F=μ02πI1I2ld

Since the current are in opposite direction, they will repel each other.

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Problem Details

Two long, parallel wires are separated by a distance of 0.400 m (fig. E28.29). The currents I1 and I2 have the directions shown.

(a) Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other. I s the for attractive or repulsive?

(b) Each current is doubled, so that I1 becomes 10.0 A and I2 becomes 4.00 A. Now what is the magnitude of the force that each wire exerts on a 1.20-m length of the other? 


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