Problem: A proton has an initial speed of 3.9 × 105 m/s.What potential difference is required to reduce the initial speed of the proton by a factor of 3?

FREE Expert Solution

Law of conservation of energy:

Ki+Ui=Kf+Uf12mvi2+qVi=12mvf2+qVf

The final speed of the proton is:

vf = vi/3 = (3.9 × 105)/3 = 1.3 × 105 m/s

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Problem Details

A proton has an initial speed of 3.9 × 105 m/s.

What potential difference is required to reduce the initial speed of the proton by a factor of 3?

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