# Problem: If the pressure reading of your pitot tube is 15.0 mmHg at a speed of 200 km/h, what will it be at 700 km/h at the same altitude?

###### FREE Expert Solution

Bernoulli's equation:

$\overline{){{\mathbf{P}}}_{{\mathbf{1}}}{\mathbf{+}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{\rho }}{{{\mathbf{v}}}_{{\mathbf{1}}}}^{{\mathbf{2}}}{\mathbf{+}}{{\mathbf{h}}}_{{\mathbf{1}}}{\mathbf{\rho }}{\mathbf{g}}{\mathbf{=}}{{\mathbf{P}}}_{{\mathbf{2}}}{\mathbf{+}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{\rho }}{{\mathbf{v}}_{\mathbf{2}}}^{{\mathbf{2}}}{\mathbf{+}}{{\mathbf{h}}}_{{\mathbf{2}}}{\mathbf{\rho }}{\mathbf{g}}}$

P1 + (1/2)ρv12 + h1ρg = P2 + (1/2)ρv22 + h2ρh

h1 = h2 (same altitude), thus we'll drop the terms involving h.

###### Problem Details

If the pressure reading of your pitot tube is 15.0 mmHg at a speed of 200 km/h, what will it be at 700 km/h at the same altitude?