Problem: A proton with an initial speed of 650,000 m/s is brought to rest by an electric field.1. What was the potential difference that stopped the proton?2. What was the initial kinetic energy of the proton, in electron volts?

FREE Expert Solution

Kinetic energy:

K.E=12mv2

Potential energy:

U=qV, where V is the potential, and q is the charge.

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Problem Details

A proton with an initial speed of 650,000 m/s is brought to rest by an electric field.

1. What was the potential difference that stopped the proton?

2. What was the initial kinetic energy of the proton, in electron volts?

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