The separation between the object and the image is 2.4m
Therefore, so + si = 2.4
si = 2.4 - so
Substituting to the lens equation:
1/so + 1/(2.4 - so) = 1/(55 × 10-2)
An object and its lens-produced real image are 2.4 m apart. If the lens has 55-cm focal length, what are the possible values for the object distance and magnification?
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