The maximum value of the current is dependent on impedance, X_{L} only, through the equation:

$\overline{){{\mathbf{i}}}_{{\mathbf{max}}}{\mathbf{=}}\frac{{\mathbf{V}}_{\mathbf{0}}}{{\mathbf{X}}_{\mathbf{L}}}}$, where V_{0} is the AC voltage.

DC circuits with an inductor are relatively simple - as we saw in the previous part, the inductor simply delays the current reaching its maximum value after the switch is closed. Then the current is constant (as if the inductor were not even there). So let's now consider an inductor circuit containing an AC voltage source. Construct a circuit containing an AC voltage source, a resistor, an inductor, and a switch, as shown in the figure. (Right-click or control-click on the AC source to set its peak voltage and its frequency as shown in the pop-up windows in the figure.) Select the Current Chart, and place the sensor over one of the wires of the circuit.

How does the maximum value of the current depend on the frequency of the AC voltage source?

A) Higher frequencies cause the maximum current to increase

B) Higher frequencies cause the maximum current to decrease.

C) The maximum current does not depend on the frequency

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