Problem: A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 N/m. At t = 0 the block has velocity -4.00 m/s and displacement +0.200 m.Find (a) the amplitude and (b) the phase angle Write an equation for the position as a function of time. Assume x(t) in meters and t in seconds.

FREE Expert Solution

(a)

Mechanical energy of a SHM oscilator:

12kA2=12kx2+12mvx2

At t = 0, x = 0.200 m and v = -4.00 m/s

A=kx2+mvx2k=(300)(0.200)2+(2.00)(-4.00)2300

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Problem Details

A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 N/m. At t = 0 the block has velocity -4.00 m/s and displacement +0.200 m.

Find (a) the amplitude and (b) the phase angle 

Write an equation for the position as a function of time. Assume x(t) in meters and t in seconds.

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Our tutors have indicated that to solve this problem you will need to apply the Energy in Simple Harmonic Motion concept. You can view video lessons to learn Energy in Simple Harmonic Motion. Or if you need more Energy in Simple Harmonic Motion practice, you can also practice Energy in Simple Harmonic Motion practice problems.