2D vector Direction/Components:
29 lb force
θ = tan-1 (y/x) = tan-1 (80/84) = 43.6°
Fx = Fcosθ = 29cos43.6 = 21.0 lb
Fy = Fsinθ = 29sin43.6 = 20.0 lb
Determine the x and y components of each of the forces shown.
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