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Problem: A 108 A current circulates around a 2.40-mm-diameter superconducting ring.1. What is the ring's magnetic dipole moment?2. What is the on-axis magnetic field strength 4.70 cm from the ring?

FREE Expert Solution

1.

Magnetic moment:

μ=iA

r = d/2 = ((2.40mm)/2)(1m/1000mm) = 1.20 × 10-3 m

μ = iA = iπr2 = (108)(π)(1.20 × 10-3)2 

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Problem Details

A 108 A current circulates around a 2.40-mm-diameter superconducting ring.


1. What is the ring's magnetic dipole moment?

2. What is the on-axis magnetic field strength 4.70 cm from the ring?

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