It's observable that tan θa = L/d0
Therefore, L = d0 tan θa
The expression for L is d0 tan θa.
The numerical value of L is:
A fisherman spots a fish underneath the water. It appears that the fish is d0 = 0.78 m under the water surface at an angle of θa = 68° with respect to the normal to the surface of the water. The index of refraction of water is nw = 1.3 and the index of refraction of air is na = 1.
(a) The perpendicular distance from the apparent position of the fish to the normal of the water surface shown in the figure is L. Express L in terms of tan θa and d0.
(b) Solve for the numerical value of L, in meters.
(c) Express the sine of the angle θw, in terms of θa, nw, and na.
(d) Solve for the numerical value of in degrees.
(e) Now assume that the real position of the fish is directly below the apparent position, as shown in the figure. Express the real depth of the fish, d, in terms of L and tanθw.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Refraction Of Light concept. You can view video lessons to learn Refraction Of Light. Or if you need more Refraction Of Light practice, you can also practice Refraction Of Light practice problems.