Vector components:

$\overline{)\begin{array}{rcl}{\mathit{A}}_{\mathit{x}}& {\mathbf{=}}& \mathbf{\left|}\stackrel{\mathbf{\rightharpoonup}}{\mathit{A}}\mathbf{\right|}\mathbf{}\mathbf{cos}\mathbf{}\mathit{\theta}\\ {\mathit{A}}_{\mathit{y}}& {\mathbf{=}}& \mathbf{\left|}\stackrel{\mathbf{\rightharpoonup}}{\mathit{A}}\mathbf{\right|}\mathbf{}\mathbf{sin}\mathbf{}\mathit{\theta}\end{array}}$

From vector components equation:

A_{x} = (3.60) cos (70°) = 1.23m i

A_{y} = (3.60) sin (70°) = 3.38m j

A = (1.23 i + 3.38 j) m

1) For the two vectors in the figure (Figure 1), find the scalar product

Express your answer in square meters.

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