The intensity of a two-slit interference pattern is expressed as:

$\overline{){\mathbf{I}}{\mathbf{=}}{{\mathbf{I}}}_{{\mathbf{0}}}{\mathbf{c}}{\mathbf{o}}{{\mathbf{s}}}^{{\mathbf{2}}}{\mathbf{\left(}}\frac{\mathbf{\varphi}}{\mathbf{2}}{\mathbf{\right)}}}$

The path difference between the waves from the two slits:

$\overline{){\mathbf{\varphi}}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi}}{\mathbf{\lambda}}{\mathbf{(}}{{\mathbf{r}}}_{{\mathbf{2}}}{\mathbf{-}}{{\mathbf{r}}}_{{\mathbf{1}}}{\mathbf{)}}}$

In a two-slit interference pattern, the intensity at the peak of the central maximum is I_{0}.**(a)** At a point in the pattern where the phase difference between the waves from the two slits is 62.0 degrees, what is the intensity? Give your answer as a fraction of I_{0}. (I/I_{0 }= ? )**(b)** What is the path difference for light with a wavelength of 473 nm from the two slits at a point where the phase angle is 62.0 degrees?

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