Young's Double Slit Experiment Video Lessons

Concept

# Problem: In a two-slit interference pattern, the intensity at the peak of the central maximum is I0.(a) At a point in the pattern where the phase difference between the waves from the two slits is 62.0 degrees, what is the intensity? Give your answer as a fraction of I0. (I/I0 = ? )(b) What is the path difference for light with a wavelength of 473 nm from the two slits at a point where the phase angle is 62.0 degrees?

###### FREE Expert Solution

The intensity of a two-slit interference pattern is expressed as:

$\overline{){\mathbf{I}}{\mathbf{=}}{{\mathbf{I}}}_{{\mathbf{0}}}{\mathbf{c}}{\mathbf{o}}{{\mathbf{s}}}^{{\mathbf{2}}}{\mathbf{\left(}}\frac{\mathbf{\varphi }}{\mathbf{2}}{\mathbf{\right)}}}$

The path difference between the waves from the two slits:

$\overline{){\mathbf{\varphi }}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi }}{\mathbf{\lambda }}{\mathbf{\left(}}{{\mathbf{r}}}_{{\mathbf{2}}}{\mathbf{-}}{{\mathbf{r}}}_{{\mathbf{1}}}{\mathbf{\right)}}}$

###### Problem Details

In a two-slit interference pattern, the intensity at the peak of the central maximum is I0.
(a) At a point in the pattern where the phase difference between the waves from the two slits is 62.0 degrees, what is the intensity? Give your answer as a fraction of I0. (I/I= ? )
(b) What is the path difference for light with a wavelength of 473 nm from the two slits at a point where the phase angle is 62.0 degrees?