The cross-sectional area of the solenoid:
A = πr2
r = 2.4/2 = 1.2 cm
A = (π)(1.2 × 10-2)2 = 4.524 × 10-4 m2
The 2.4-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.30 T.
Part A What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express your answer in webers.
Part B What is the magnetic flux through the loop when it is tilted at a 60 angle? Express your answer in webers.
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