# Problem: Two 2.10 cm × 2.10 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC.Part AWhat is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm?Part BWhat is the potential difference across the capacitor if the spacing between the plates is 2.60 mm?Show your work.

###### FREE Expert Solution

Part A

Electric field strength inside the capacitor is:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{d}}}$

The potential difference between the plates is:

$\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{Q}}{\mathbf{C}}}$

Capacitance C is:

$\overline{){\mathbf{C}}{\mathbf{=}}{{\mathbf{\epsilon }}}_{{\mathbf{0}}}\frac{\mathbf{A}}{\mathbf{d}}}$ ###### Problem Details

Two 2.10 cm × 2.10 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC.

Part A

What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm?

Part B

What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm?