**Part A**

Electric field strength inside the capacitor is:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{d}}}$

The potential difference between the plates is:

$\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{Q}}{\mathbf{C}}}$

Capacitance C is:

$\overline{){\mathbf{C}}{\mathbf{=}}{{\mathbf{\epsilon}}}_{{\mathbf{0}}}\frac{\mathbf{A}}{\mathbf{d}}}$

Two 2.10 cm × 2.10 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC.

**Part A**

What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm?

**Part B**

What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm?

Show your work.

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