Problem: Consider a system consisting of three particles: m1 = 2 kg, v1  < 10, -5, 12 > m/s m2 = 9 kg, v2 <- 14, 3, -3>m/s m3 = 2 kg, v3 <- 23, 37, 20 > m/s What Is the velocity of the center of mass of thls system? vcm = m/s

FREE Expert Solution

Velocity of the center of mass:

vCM=ΣmiviΣmi

vCM,x = Σmivix/Σmi = (m1v1x + m2v2x + m3v3x)/(m1 + m2 + m3) = [(2)(10) + (9)(-14) + (2)(-23)]/(2 + 9 + 2) = -11.7 m/s

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Problem Details

Consider a system consisting of three particles: 

m1 = 2 kg, v1  < 10, -5, 12 > m/s 

m= 9 kg, v<- 14, 3, -3>m/s 

m= 2 kg, v<- 23, 37, 20 > m/s 

What Is the velocity of the center of mass of thls system? 

vcm = m/s

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