Velocity of the center of mass:
vCM,x = Σmivix/Σmi = (m1v1x + m2v2x + m3v3x)/(m1 + m2 + m3) = [(2)(10) + (9)(-14) + (2)(-23)]/(2 + 9 + 2) = -11.7 m/s
Consider a system consisting of three particles:
m1 = 2 kg, v1 < 10, -5, 12 > m/s
m2 = 9 kg, v2 <- 14, 3, -3>m/s
m3 = 2 kg, v3 <- 23, 37, 20 > m/s
What Is the velocity of the center of mass of thls system?
vcm = m/s
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