Velocity of the center of mass:

$\overline{){\stackrel{\mathbf{\rightharpoonup}}{\mathbf{v}}}_{\mathbf{C}\mathbf{M}}{\mathbf{=}}\frac{\mathbf{\Sigma}{\mathbf{m}}_{\mathbf{i}}{\mathbf{v}}_{\mathbf{i}}}{\mathbf{\Sigma}{\mathbf{m}}_{\mathbf{i}}}}$

v_{CM,x} = Σm_{i}v_{ix}/Σm_{i} = (m_{1}v_{1x} + m_{2}v_{2x} + m_{3}v_{3x})/(m_{1} + m_{2} + m_{3}) = [(2)(10) + (9)(-14) + (2)(-23)]/(2 + 9 + 2) = -11.7 m/s

Consider a system consisting of three particles:

m_{1} = 2 kg, v_{1} < 10, -5, 12 > m/s

m_{2 }= 9 kg, v_{2 }<- 14, 3, -3>m/s

m_{3 }= 2 kg, v_{3 }<- 23, 37, 20 > m/s

What Is the velocity of the center of mass of thls system?

v_{cm} = m/s

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