Ohm's law:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{i}}{\mathbf{R}}}$

At resonance,

Z = R

X_{c} = 1/(ω_{0}C)

Current in the circuit, i = V_{max}/Z = **V _{max}/R**

In an L-R-C series circuit, the resistance is R = 460Ω, the inductance is L = 0.360 H, the capacitance is C = 2.00 × 10^{-2} µF and the resonant angular frequency is 11785 rad/s.

The capacitor can withstand a peak voltage of 560 volts. If the voltage source operates at the resonance frequency, what maximum voltage amplitude can the source have if the maximum capacitor voltage is not exceeded?

Express your answer in volts to three significant figures.

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