Let's label the diagram as follows:
From Kirchhoff's loop rule, ΣV = 0
V = iR
If the current is counterclockwise, the potential difference is positive.
If the current is flowing in a clockwise direction, then the potential difference is negative.
Let's apply the Kirchhoff's loop rule to the upper loop ABCFA:
i12.96R - is - i2R = 0
In Fig. 27-57, R1 = 2.96 R, the ammeter resistance is zero, and the battery is ideal. What multiple of ε/R gives the current in the ammeter?
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