Let's label the diagram as follows:

From Kirchhoff's loop rule, ΣV = 0

V = iR

If the current is counterclockwise, the potential difference is positive.

If the current is flowing in a clockwise direction, then the potential difference is negative.

Let's apply the Kirchhoff's loop rule to the upper loop ABCFA:

i_{1}2.96R - is - i_{2}R = 0

In Fig. 27-57, R_{1} = 2.96 R, the ammeter resistance is zero, and the battery is ideal. What multiple of ε/R gives the current in the ammeter?

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