# Problem: Consider a system consisting of three particles: m1 = 2 kg, v1  &lt; 10, -5, 12 &gt; m/s m2 = 9 kg, v2 &lt;- 14, 3, -3&gt;m/s m3 = 2 kg, v3 &lt;- 23, 37, 20 &gt; m/s What Is the total momentum of this system? ptot = kg m/s

###### FREE Expert Solution

Momentum:

$\overline{){\mathbf{p}}{\mathbf{=}}{\mathbf{m}}{\mathbf{v}}}$

Ptot = (px, py, pz)

px = m1v1x + m2v2x + m3v3x = (2)(10) + (9)(-14) + (2)(-23) = -152 kg•m/s

87% (444 ratings) ###### Problem Details

Consider a system consisting of three particles:

m1 = 2 kg, v1  < 10, -5, 12 > m/s

m= 9 kg, v<- 14, 3, -3>m/s

m= 2 kg, v<- 23, 37, 20 > m/s

What Is the total momentum of this system?

ptot = kg m/s

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