# Problem: The magnetic field of an electromagnetic wave in a vacuum is Bz =(3.8μT)sin((9.50×10^6)x−ωt), where x is in m and t is in s.A) What is the wave's wavelength?B) What is the wave's frequency?C) What is the wave's electric field amplitude?

###### FREE Expert Solution

Wave number, k is always given as:

$\overline{){\mathbf{k}}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi }}{\mathbf{\lambda }}}$

Frequency:

$\overline{){\mathbf{f}}{\mathbf{=}}\frac{\mathbf{c}}{\mathbf{\lambda }}}$

A)

From the wavenumber equation, we get the wavelength of the wave as:

λ = 2π/k

###### Problem Details

The magnetic field of an electromagnetic wave in a vacuum is Bz =(3.8μT)sin((9.50×10^6)x−ωt), where x is in m and t is in s.

A) What is the wave's wavelength?

B) What is the wave's frequency?

C) What is the wave's electric field amplitude?