Conservation of energy:

$\overline{){{\mathbf{U}}}_{{\mathbf{0}}}{\mathbf{}}{\mathbf{+}}{\mathbf{}}{\mathbf{K}}{{\mathbf{E}}}_{{\mathbf{0}}}{\mathbf{}}{\mathbf{+}}{\mathbf{}}{{\mathbf{W}}}_{\mathbf{n}\mathbf{c}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{{\mathbf{U}}}_{{\mathbf{f}}}{\mathbf{}}{\mathbf{+}}{\mathbf{}}{\mathbf{K}}{{\mathbf{E}}}_{{\mathbf{f}}}}$

Potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}{\mathbf{m}}{\mathbf{g}}{\mathbf{h}}}$

Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

KE_{0} = 0 (velocity at a is zero).

U_{0} = mgh_{A}

Work done by non-conservative forces, W_{nc} is zero.

U_{f} = mgh_{T}

A particle slides along the frictionless track shown in the figure, starting at rest from point *A*.

Find the approximate location of its right-hand turning point.

Express your answer using two significant figures.

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