**1.**

Electric field due to the two parallel plates:

$\begin{array}{rcl}E& =& \frac{\mathbf{\sigma}}{\mathbf{2}{\mathbf{\epsilon}}_{\mathbf{0}}}\mathbf{+}\frac{\mathbf{\sigma}}{\mathbf{2}{\mathbf{\epsilon}}_{\mathbf{0}}}\\ & =& \frac{\mathbf{\sigma}}{{\mathbf{\epsilon}}_{\mathbf{0}}}\end{array}$

Two 2.70 cm times 2.70 cm plates that form a parallel-plate capacitor are charged ± 0.708 nC.

1. What is the electric field strength inside the capacitor if the spacing between the plates is 2.40 mm?

2. What is the potential difference across the capacitor if the spacing between the plates is 240 mm?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Electric Fields in Capacitors concept. You can view video lessons to learn Electric Fields in Capacitors. Or if you need more Electric Fields in Capacitors practice, you can also practice Electric Fields in Capacitors practice problems.