Power:

$\overline{){\mathbf{P}}{\mathbf{=}}\frac{\mathbf{W}}{\mathbf{t}}}$

Where P is power, W is work and t is time.

Work:

$\overline{){\mathbf{W}}{\mathbf{=}}{{\mathbf{Q}}}_{\mathbf{i}\mathbf{n}}{\mathbf{-}}{{\mathbf{Q}}}_{\mathbf{o}\mathbf{u}\mathbf{t}}}$

Frequency:

$\overline{){\mathbf{f}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{T}}}$

where T is periodic time.

(1/t) = f

P = W/t = (Q_{in} - Q_{out})•f

Rank these engines on the basis of their designed power output. Rank from largest to smallest. To rank items as equivalent, overlap them.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

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