**(1)**

Applying Kirchoff's loop rule to the left loop:

ε - (30.0)i_{1} = 0

i_{1} = ε/30.0 = 8.00/30.0 = 0.267 A

The batteries shown in the circuit in (Figure 1) have negligibly small internal resistances. Assume that & 8.00 negligibly small internal resistances. Assume that-8.00 V and R = 21.9 Ω.

1.

Find the current through the 30.0 Ω resistor.

Express your answer in amperes to three significant figures

2.

Find the current through the 21.9 Ω resistor.

Express your answer in amperes to three significant figures

3.

Find the current through the 8.00 V battery.

Express your answer in amperes to three significant figures

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