Peak current through the resistor is given by:

$\overline{){\mathbf{i}}{\mathbf{=}}\frac{{\mathbf{\epsilon}}_{\mathbf{0}}}{\mathbf{R}}}$

**a.**

From the above equation, the peak current is inversely proportional to resistance.

Therefore, if the resistance is doubled, the peak current will be halved.

A resistor is connected across an oscillating emf. The peak current through the resistor is 2.0 A. What is the peak current if:

a. The resistance R is doubled?

b. The peak emf ε_{0} is doubled?

c. The frequency ω is doubled?

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