Let the magnitude of the applied force be F, and the distance between the line of action and axis of rotation be r.

Torque is then given as:

$\overline{){\mathbf{\tau}}{\mathbf{=}}{\mathbf{F}}{\mathbf{\times}}{\mathbf{r}}}$

The line of rotation is along the direction of the force applied. The axis of rotation is at P.

r = x sin ɸ

Find T_{F}, the torque about point P due to the force applied by the Achilles' tendon.

Express your answer in terms of F, phi, and x.

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