# Problem: The photoelectric threshold wavelength of a tungsten surface is 272 nm .Part AWhat is the threshold frequency of this tungsten?Part BWhat is the work function (in eV ) of this tungsten?Part CCalculate the maximum kinetic energy (in eV ) of the electrons ejected from this tungsten surface by ultraviolet radiation of frequency 1.48×1015 Hz.

###### FREE Expert Solution

Speed of light:

$\overline{){\mathbf{c}}{\mathbf{=}}{\mathbf{f}}{\mathbf{\lambda }}}$

$\overline{){\mathbf{E}}{\mathbf{=}}{\mathbf{h}}{\mathbf{f}}}$

h is plank's constant.

(A)

f = c/λ = (3.0 × 108)/(272 × 10-9) = 1.10 × 1015 hz

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###### Problem Details

The photoelectric threshold wavelength of a tungsten surface is 272 nm .

Part A

What is the threshold frequency of this tungsten?

Part B

What is the work function (in eV ) of this tungsten?

Part C

Calculate the maximum kinetic energy (in eV ) of the electrons ejected from this tungsten surface by ultraviolet radiation of frequency 1.48×1015 Hz.