# Problem: A parallel-plate capacitor is charged by a 17.0 V battery, then the battery is removed. What is the potential difference between the plates after the battery is disconnected? What is the potential difference between the plates after a sheet of Teflon is inserted between them?

###### FREE Expert Solution

The capacitance of a parallel plate capacitor:

$\overline{){\mathbf{C}}{\mathbf{=}}\frac{{\mathbf{\epsilon }}_{\mathbf{0}}\mathbf{A}}{\mathbf{d}}}$

The charge stored in a capacitor:

$\overline{){\mathbf{Q}}{\mathbf{=}}{\mathbf{C}}{\mathbf{V}}}$

(a)

The capacitor is charged to V = 17 V.

V = Q/C = 17 V

The potential difference will change if the charge, Q, or the capacitance, C, are changed.

97% (258 ratings) ###### Problem Details

A parallel-plate capacitor is charged by a 17.0 V battery, then the battery is removed. What is the potential difference between the plates after the battery is disconnected? What is the potential difference between the plates after a sheet of Teflon is inserted between them?