Problem: A parallel-plate capacitor is charged by a 17.0 V battery, then the battery is removed. What is the potential difference between the plates after the battery is disconnected? What is the potential difference between the plates after a sheet of Teflon is inserted between them?

FREE Expert Solution

The capacitance of a parallel plate capacitor:

C=ε0Ad

The charge stored in a capacitor:

Q=CV

(a)

The capacitor is charged to V = 17 V.

V = Q/C = 17 V

The potential difference will change if the charge, Q, or the capacitance, C, are changed.

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Problem Details

A parallel-plate capacitor is charged by a 17.0 V battery, then the battery is removed. What is the potential difference between the plates after the battery is disconnected? What is the potential difference between the plates after a sheet of Teflon is inserted between them?

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