Weight, W = mg
The weight of the sign is given by:
Ws = mg = (10)(9.8) = 98 N.
In the horizontal direction, the forces are:
- TAcos(45°) + TB cos (30°) = 0
Along the vertical direction:
TA sin (45°) + TB sin (30°) - Ws = 0
A 10-kg sign is held by two ropes as shown in the figure below. What is the tension on rope A?
a. 44 N
b. 88 N
c. 69 N
d. 98 N
e. 72 N
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Our tutors have indicated that to solve this problem you will need to apply the 2D Equilibrium concept. You can view video lessons to learn 2D Equilibrium. Or if you need more 2D Equilibrium practice, you can also practice 2D Equilibrium practice problems.
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