Area of a side of the cube = 0.06 × 0.06 = 0.0036m2
The angle between side one and the electric field is 150°
Φ1 = EAcosθ = (500)(0.0036)cos150 = -1.56N•m2/C
The figure(Figure 1) shows four sides of a 6.0cm×6.0cm×6.0cm cube.
(a) What is the electric flux Φ1 through side 1?
(b) What is the electric flux Φ2 through side 2?
(c) What is the electric flux Φ3 through side 3?
(d) What is the electric fluxe Φ4 through side 4?
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