Snell's law:

$\overline{){{\mathbf{\eta}}}_{{\mathbf{1}}}{\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{{\mathbf{\theta}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{\eta}}}_{{\mathbf{2}}}{\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{{\mathbf{\theta}}}_{{\mathbf{2}}}}$

For easy reference, let's label our figure as below:

(1)sin(40.0°) = (1.52) sin (θ_{2})

θ_{2} = sin^{-1} [sin(40.0°)/1.52] = 25°

Calculate the distance the ray is displaced, in millimeters by the glass, given that the incident angle is 40.0 the glass is 0.95 cm thick. Take 1.52 for the index of refraction for crown glass.

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