Problem: A 9.0×10−2 g plastic bead is charged by the addition of 1.0×1010 excess electrons.Part AWhat electric field E⃗  (strength) will cause the bead to hang suspended in the air?Part BWhat electric field E⃗  (direction) will cause the bead to hang suspended in the air?

FREE Expert Solution

Electric force:

F=qE

Weight:

w=mg

(a)

When the ball is suspended, the sum of forces on the ball is zero.

q = Ne = (1.0 × 1010)(1.6 × 10-19) = 1.6 × 10-9 C

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Problem Details

A 9.0×10−2 g plastic bead is charged by the addition of 1.0×1010 excess electrons.

Part A

What electric field E⃗  (strength) will cause the bead to hang suspended in the air?

Part B

What electric field E⃗  (direction) will cause the bead to hang suspended in the air?

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