Problem: The switch in the figure has been in position a for a long time. It is changed to position b at t = 0 s.A. What is the charge Q on the capacitor at t = 50 µs?B. What is the current I through the resistor at t = 50 µs?

FREE Expert Solution

Charge decay formula is:

Q(t)=CV0(e-tτ)

Expression of voltage across the capacitor is:

VC(t)=V0e-tRC

This is because the time constant τ is given as, τ = RC

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Problem Details


The switch in the figure has been in position a for a long time. It is changed to position b at t = 0 s.

A. What is the charge Q on the capacitor at t = 50 µs?

B. What is the current I through the resistor at t = 50 µs?

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