Simple Harmonic Motion of Vertical Springs Video Lessons

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Problem: The device pictured in Figure 16.4 entertains infants while keeping them from wandering. The child bounces un a harness suspended from a door frame by a spring constant - K = 313.6 N/m.What is the child's maximum velocity if the amplitude of her bounce is 0.200 m? (Mass of the child is 8.0 kg).

FREE Expert Solution

Kinetic energy:

KE=12mv2

The potential energy of a simple harmonic oscillator:

U=12KA2

From the principal of conservation of energy, the maximum kinetic energy of a simple harmonic oscillator is equal to the maximum potential energy:

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Problem Details

The device pictured in Figure 16.4 entertains infants while keeping them from wandering. The child bounces un a harness suspended from a door frame by a spring constant - K = 313.6 N/m.

What is the child's maximum velocity if the amplitude of her bounce is 0.200 m? (Mass of the child is 8.0 kg).

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