Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

The potential energy of a simple harmonic oscillator:

$\overline{){\mathbf{U}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{K}}{{\mathbf{A}}}^{{\mathbf{2}}}}$

From the principal of conservation of energy, the maximum kinetic energy of a simple harmonic oscillator is equal to the maximum potential energy:

The device pictured in Figure 16.4 entertains infants while keeping them from wandering. The child bounces un a harness suspended from a door frame by a spring constant - K = 313.6 N/m.

What is the child's maximum velocity if the amplitude of her bounce is 0.200 m? (Mass of the child is 8.0 kg).

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Simple Harmonic Motion of Vertical Springs concept. You can view video lessons to learn Simple Harmonic Motion of Vertical Springs. Or if you need more Simple Harmonic Motion of Vertical Springs practice, you can also practice Simple Harmonic Motion of Vertical Springs practice problems.