Potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}{\mathbf{m}}{\mathbf{g}}{\mathbf{h}}}$

Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

At maximum speed, the kinetic energy is maximum. According to the conservation of energy, all the potential energy is converted into kinetic energy.

KE_{max} = U_{max}

(1/2)mv_{max}^{2} = mgh_{max}

v = (2gh_{max})^{(1/2)}

Rank each pendulum on the basis of its maximum speed.

Rank from largest to smallest.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Simple Harmonic Motion of Pendulums concept. You can view video lessons to learn Simple Harmonic Motion of Pendulums. Or if you need more Simple Harmonic Motion of Pendulums practice, you can also practice Simple Harmonic Motion of Pendulums practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Lopez Lozano's class at UTSA.