The maximum speed of an object on a spring undergoing a simple harmonic motion can be expressed as:

$\overline{){{\mathbf{v}}}_{\mathbf{m}\mathbf{a}\mathbf{x}}{\mathbf{=}}{\mathbf{\omega}}{\mathbf{A}}}$

But,

$\overline{){\mathbf{\omega}}{\mathbf{=}}\sqrt{\frac{\mathbf{k}}{\mathbf{m}}}}$

Therefore,

$\begin{array}{rcl}{\mathbf{v}}_{\mathbf{m}\mathbf{a}\mathbf{x}}& \mathbf{=}& \mathbf{\left(}\sqrt{\frac{\mathbf{k}}{\mathbf{m}}}\mathbf{\right)}\mathbf{A}\end{array}$

You can double the maximum speed of an object on a spring undergoing simple harmonic motion by:

a. Reducing the mass to one-fourth its original value

b. All of these

c. Doubling the amplitude

d. None of these

e. Increasing the spring constant to four times its original value

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Intro to Simple Harmonic Motion (Horizontal Springs) concept. You can view video lessons to learn Intro to Simple Harmonic Motion (Horizontal Springs). Or if you need more Intro to Simple Harmonic Motion (Horizontal Springs) practice, you can also practice Intro to Simple Harmonic Motion (Horizontal Springs) practice problems.