Electric Potential Energy Video Lessons

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Problem: A point charge with a charge q1 = 3.10 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC moves from the point x = 0.130 m , y = 0 to the point x = 0.230 m , y = 0.290 m.How much work is done by the electric force on q2?

FREE Expert Solution

The work done:

W=E=Ef-Ei

Electric potential energy:

E=-kq1q2r

Initial electric potential energy:

Ei=-(8.99×109)[(3.10×10-6)(-4.10×10-6)0.130]

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Problem Details

A point charge with a charge q1 = 3.10 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC moves from the point x = 0.130 m , y = 0 to the point x = 0.230 m , y = 0.290 m.

How much work is done by the electric force on q2?

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