Equivalent resistance for two resistors in parallel:
Current when the switch is open:
1.636 = ε/(r + 5.0)
When the switch is closed, the current through the 5.0-Ω resistor is:
i1 = 1.565A
Voltage, V = i1R
V = i1(5.0) = (1.565)(5.0) = 7.825 V
The potential across the 10.0-Ω resistor is:
V = 7.825 V
Current across the 10.0-Ω resistor is:
i2 = 7.825/10.0 = 0.7825A
When teh switch is closed,
i = i1 + i2 = 1.565 + 0.7825 = 2.3475A
The resistors are in parallel:
Req = (5.0)(10.0)/(5.0 + 10.0) = 3.333Ω
A) What is the emf of the battery in the figure ?
B) What is the internal resistance of the battery in the figure?
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