Trig Review Video Lessons

Concept

# Problem: V is a vector 24.8 units in magnitude and points an angle of 23.4° above the negative axis.(a) Sketch this vector.(b) Calculate Vx and Vy.(c) Use Vx and Vy to obtain (again) the magnitude of V. [ Note: Part (c) is a good way to check if you've resolved your vector correctly.](d) Use Vx and Vy to obtain (again) the direction of V.

###### FREE Expert Solution

2D vector Magnitude:

$\overline{)\mathbf{|}\stackrel{\mathbf{⇀}}{\mathbf{v}}\mathbf{|}{\mathbf{=}}\sqrt{{{\mathbf{v}}_{\mathbf{x}}}^{\mathbf{2}}\mathbf{+}{{\mathbf{v}}_{\mathbf{y}}}^{\mathbf{2}}}}$

2D vector direction:

$\overline{){\mathbf{tan}}{\mathbit{\theta }}{\mathbf{=}}\frac{{\mathbit{v}}_{\mathbit{y}}}{{\mathbit{v}}_{\mathbit{x}}}}$

Vector decomposition:

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###### Problem Details

V is a vector 24.8 units in magnitude and points an angle of 23.4° above the negative axis.
(a) Sketch this vector.
(b) Calculate Vx and Vy.
(c) Use Vx and Vy to obtain (again) the magnitude of V. [ Note: Part (c) is a good way to check if you've resolved your vector correctly.]
(d) Use Vx and Vy to obtain (again) the direction of V.