Problem: An electron with an initial speed of 5.50×105 is brought to rest by an electric field. (a) Did the electron move into a region of higher potential or lower potential? (b) What was the potential difference that stopped the electron? In V (c) What was the initial kinetic energy of the electron, in electron volts? In eV

FREE Expert Solution

Kinetic Energy:

K.E=12mv2

Electric potential energy:

U=qV

(a)

Electrons move in a direction opposite the electric field. The electric field points in the direction of decreasing potential.

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Problem Details

An electron with an initial speed of 5.50×105 is brought to rest by an electric field. 

(a) Did the electron move into a region of higher potential or lower potential?
(b) What was the potential difference that stopped the electron? In V
(c) What was the initial kinetic energy of the electron, in electron volts? In eV

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